Divide Using Long Polynomial Division (2b^3-6b^2+8b)÷(2b^2+b+1)

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Algebra

$(2 b^{3} - 6 b^{2} + 8 b) \div (2 b^{2} + b + 1)$

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

Divide the highest order term in the dividend $2 b^{3}$ by the highest order term in divisor $2 b^{2}$ .

$b$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

Multiply the new quotient term by the divisor.

$b$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

The expression needs to be subtracted from the dividend, so change all the signs in $2 b^{3} + b^{2} + b$

$b$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$b$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

$7 b^{2}$

$7 b$

Pull the next terms from the original dividend down into the current dividend.

$b$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

$7 b^{2}$

$7 b$

$0$

Divide the highest order term in the dividend $- 7 b^{2}$ by the highest order term in divisor $2 b^{2}$ .

$b$

$\frac{7}{2}$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

$7 b^{2}$

$7 b$

$0$

Multiply the new quotient term by the divisor.

$b$

$\frac{7}{2}$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

$7 b^{2}$

$7 b$

$0$

$7 b^{2}$

$\frac{7 b}{2}$

$\frac{7}{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $- 7 b^{2} - \frac{7 b}{2} - \frac{7}{2}$

$b$

$\frac{7}{2}$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

$7 b^{2}$

$7 b$

$0$

$7 b^{2}$

$\frac{7 b}{2}$

$\frac{7}{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$b$

$\frac{7}{2}$

$2 b^{2}$

$b$

$1$

$2 b^{3}$

$6 b^{2}$

$8 b$

$0$

$2 b^{3}$

$b^{2}$

$b$

$7 b^{2}$

$7 b$

$0$

$7 b^{2}$

$\frac{7 b}{2}$

$\frac{7}{2}$

$\frac{21 b}{2}$

$\frac{7}{2}$

The final answer is the quotient plus the remainder over the divisor.

$b - \frac{7}{2} + \frac{\frac{21 b}{2} + \frac{7}{2}}{2 b^{2} + b + 1}$

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