Graph x/(x+4)>=2

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Graph x/(x+4)>=2

$\frac{x}{x + 4} \geq 2$

Subtract $2$ from both sides of the inequality.

$\frac{x}{x + 4} - 2 \geq 0$

Simplify $\frac{x}{x + 4} - 2$ .

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To write $- 2$ as a fraction with a common denominator, multiply by $\frac{x + 4}{x + 4}$ .

$\frac{x}{x + 4} - 2 \cdot \frac{x + 4}{x + 4} \geq 0$

Combine $- 2$ and $\frac{x + 4}{x + 4}$ .

$\frac{x}{x + 4} + \frac{- 2 (x + 4)}{x + 4} \geq 0$

Combine the numerators over the common denominator.

$\frac{x - 2 (x + 4)}{x + 4} \geq 0$

Simplify the numerator.

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Apply the distributive property.

$\frac{x - 2 x - 2 \cdot 4}{x + 4} \geq 0$

Multiply $- 2$ by $4$ .

$\frac{x - 2 x - 8}{x + 4} \geq 0$

Subtract $2 x$ from $x$ .

$\frac{- x - 8}{x + 4} \geq 0$

Factor $- 1$ out of $- x$ .

$\frac{- (x) - 8}{x + 4} \geq 0$

Rewrite $- 8$ as $- 1 (8)$ .

$\frac{- (x) - 1 (8)}{x + 4} \geq 0$

Factor $- 1$ out of $- (x) - 1 (8)$ .

$\frac{- (x + 8)}{x + 4} \geq 0$

Rewrite $- (x + 8)$ as $- 1 (x + 8)$ .

$\frac{- 1 (x + 8)}{x + 4} \geq 0$

Move the negative in front of the fraction.

$- \frac{x + 8}{x + 4} \geq 0$

Find all the values where the expression switches from negative to positive by setting each factor equal to $0$ and solving.

$x + 8 = 0$

$x + 4 = 0$

Subtract $8$ from both sides of the equation.

$x = - 8$

Subtract $4$ from both sides of the equation.

$x = - 4$

Solve for each factor to find the values where the absolute value expression goes from negative to positive.

$x = - 8$

$x = - 4$

Consolidate the solutions.

$x = - 8, - 4$

Find the domain of $- \frac{x + 8}{x + 4}$ .

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Set the denominator in $\frac{x + 8}{x + 4}$ equal to $0$ to find where the expression is undefined.

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

The domain is all values of $x$ that make the expression defined.

$(- \infty, - 4) \cup (- 4, \infty)$

Use each root to create test intervals.

$x < - 8$

$- 8 < x < - 4$

$x > - 4$

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

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Test a value on the interval $x < - 8$ to see if it makes the inequality true.

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Choose a value on the interval $x < - 8$ and see if this value makes the original inequality true.

$x = - 10$

Replace $x$ with $- 10$ in the original inequality.

$\frac{- 10}{(- 10) + 4} \geq 2$

The left side $1.\overline{6}$ is less than the right side $2$ , which means that the given statement is false.

False

Test a value on the interval $- 8 < x < - 4$ to see if it makes the inequality true.

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Choose a value on the interval $- 8 < x < - 4$ and see if this value makes the original inequality true.

$x = - 6$

Replace $x$ with $- 6$ in the original inequality.

$\frac{- 6}{(- 6) + 4} \geq 2$

The left side $3$ is greater than the right side $2$ , which means that the given statement is always true.

True

Test a value on the interval $x > - 4$ to see if it makes the inequality true.

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Choose a value on the interval $x > - 4$ and see if this value makes the original inequality true.

$x = 0$

Replace $x$ with $0$ in the original inequality.

$\frac{0}{(0) + 4} \geq 2$

The left side $0$ is less than the right side $2$ , which means that the given statement is false.

False

Compare the intervals to determine which ones satisfy the original inequality.

$x < - 8$ False

$- 8 < x < - 4$ True

$x > - 4$ False

$x < - 8$ False

$- 8 < x < - 4$ True

$x > - 4$ False

The solution consists of all of the true intervals.

$- 8 \leq x < - 4$

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