Solve for y 2x+3y=12 for y

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Algebra

$2 x + 3 y = 12$ for $y$

Subtract $2 x$ from both sides of the equation.

$3 y = 12 - 2 x$

Divide each term in $3 y = 12 - 2 x$ by $3$ and simplify.

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Divide each term in $3 y = 12 - 2 x$ by $3$ .

$\frac{3 y}{3} = \frac{12}{3} + \frac{- 2 x}{3}$

Simplify the left side.

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Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 y}{3} = \frac{12}{3} + \frac{- 2 x}{3}$

Divide $y$ by $1$ .

$y = \frac{12}{3} + \frac{- 2 x}{3}$

Simplify the right side.

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Simplify each term.

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Divide $12$ by $3$ .

$y = 4 + \frac{- 2 x}{3}$

Move the negative in front of the fraction.

$y = 4 - \frac{2 x}{3}$

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