Solve for y 7y-4+3y+6=9y+8

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Algebra

$7 y - 4 + 3 y + 6 = 9 y + 8$

Simplify $7 y - 4 + 3 y + 6$ .

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Add $7 y$ and $3 y$ .

$10 y - 4 + 6 = 9 y + 8$

Add $- 4$ and $6$ .

$10 y + 2 = 9 y + 8$

Move all terms containing $y$ to the left side of the equation.

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Subtract $9 y$ from both sides of the equation.

$10 y + 2 - 9 y = 8$

Subtract $9 y$ from $10 y$ .

$y + 2 = 8$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $2$ from both sides of the equation.

$y = 8 - 2$

Subtract $2$ from $8$ .

$y = 6$

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