Solve the System of Equations x-4y=-8 -x+4y-8=0

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Algebra

$x - 4 y = - 8$ $- x + 4 y - 8 = 0$

Add $4 y$ to both sides of the equation.

$x = - 8 + 4 y$

$- x + 4 y - 8 = 0$

Replace all occurrences of $x$ with $- 8 + 4 y$ in each equation.

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Replace all occurrences of $x$ in $- x + 4 y - 8 = 0$ with $- 8 + 4 y$ .

$- (- 8 + 4 y) + 4 y - 8 = 0$

$x = - 8 + 4 y$

Simplify the left side.

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Simplify $- (- 8 + 4 y) + 4 y - 8$ .

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Simplify each term.

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Apply the distributive property.

$8 - (4 y) + 4 y - 8 = 0$

$x = - 8 + 4 y$

Multiply $- 1$ by $- 8$ .

$8 - (4 y) + 4 y - 8 = 0$

$x = - 8 + 4 y$

Multiply $4$ by $- 1$ .

$8 - 4 y + 4 y - 8 = 0$

$x = - 8 + 4 y$

$8 - 4 y + 4 y - 8 = 0$

$x = - 8 + 4 y$

Combine the opposite terms in $8 - 4 y + 4 y - 8$ .

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Add $- 4 y$ and $4 y$ .

$8 + 0 - 8 = 0$

$x = - 8 + 4 y$

Add $8$ and $0$ .

$8 - 8 = 0$

$x = - 8 + 4 y$

Subtract $8$ from $8$ .

$0 = 0$

$x = - 8 + 4 y$

$0 = 0$

$x = - 8 + 4 y$

$0 = 0$

$x = - 8 + 4 y$

$0 = 0$

$x = - 8 + 4 y$

$0 = 0$

$x = - 8 + 4 y$

Remove any equations from the system that are always true.

$x = - 8 + 4 y$

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