Solve for b 2b-25+5b=7-32

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Algebra

$2 b - 25 + 5 b = 7 - 32$

Add $2 b$ and $5 b$ .

$7 b - 25 = 7 - 32$

Subtract $32$ from $7$ .

$7 b - 25 = - 25$

Move all terms not containing $b$ to the right side of the equation.

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Add $25$ to both sides of the equation.

$7 b = - 25 + 25$

Add $- 25$ and $25$ .

$7 b = 0$

Divide each term in $7 b = 0$ by $7$ and simplify.

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Divide each term in $7 b = 0$ by $7$ .

$\frac{7 b}{7} = \frac{0}{7}$

Simplify the left side.

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Cancel the common factor of $7$ .

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Cancel the common factor.

$\frac{7 b}{7} = \frac{0}{7}$

Divide $b$ by $1$ .

$b = \frac{0}{7}$

Simplify the right side.

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Divide $0$ by $7$ .

$b = 0$

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