# Solve for x x^2-3(x+1)<=x-3x-3

Solve for x x^2-3(x+1)<=x-3x-3
Simplify each term.
Apply the distributive property.
Multiply by .
Subtract from .
Move all terms containing to the left side of the inequality.
Add to both sides of the inequality.
Convert the inequality to an equation.
Add to both sides of the equation.
Combine the opposite terms in .
Factor out of .
Factor out of .
Factor out of .
Factor out of .
If any individual factor on the left side of the equation is equal to , the entire expression will be equal to .
Set equal to .
Set equal to and solve for .
Set equal to .
Add to both sides of the equation.
The final solution is all the values that make true.
Use each root to create test intervals.
Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.
Test a value on the interval to see if it makes the inequality true.
Choose a value on the interval and see if this value makes the original inequality true.
Replace with in the original inequality.
The left side is greater than the right side , which means that the given statement is false.
False
False
Test a value on the interval to see if it makes the inequality true.
Choose a value on the interval and see if this value makes the original inequality true.
Replace with in the original inequality.
The left side is less than the right side , which means that the given statement is always true.
True
True
Test a value on the interval to see if it makes the inequality true.
Choose a value on the interval and see if this value makes the original inequality true.
Replace with in the original inequality.
The left side is greater than the right side , which means that the given statement is false.
False
False
Compare the intervals to determine which ones satisfy the original inequality.
False
True
False
False
True
False
The solution consists of all of the true intervals.
The result can be shown in multiple forms.
Inequality Form:
Interval Notation:
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