Evaluate ( square root of ab)/( square root of a+ square root of b)

Solve Math

Algebra

$\frac{\sqrt{a b}}{\sqrt{a} + \sqrt{b}}$

Multiply $\frac{\sqrt{a b}}{\sqrt{a} + \sqrt{b}}$ by $\frac{\sqrt{a} - \sqrt{b}}{\sqrt{a} - \sqrt{b}}$ .

$\frac{\sqrt{a b}}{\sqrt{a} + \sqrt{b}} \cdot \frac{\sqrt{a} - \sqrt{b}}{\sqrt{a} - \sqrt{b}}$

Multiply $\frac{\sqrt{a b}}{\sqrt{a} + \sqrt{b}}$ by $\frac{\sqrt{a} - \sqrt{b}}{\sqrt{a} - \sqrt{b}}$ .

$\frac{\sqrt{a b} (\sqrt{a} - \sqrt{b})}{(\sqrt{a} + \sqrt{b}) (\sqrt{a} - \sqrt{b})}$

Expand the denominator using the FOIL method.

$\frac{\sqrt{a b} (\sqrt{a} - \sqrt{b})}{{\sqrt{a}}^{2} - \sqrt{a b} + \sqrt{b a} - {\sqrt{b}}^{2}}$

Simplify.

$\frac{\sqrt{a b} (\sqrt{a} - \sqrt{b})}{a - b}$

Apply the distributive property.

$\frac{\sqrt{a b} \sqrt{a} + \sqrt{a b} (- \sqrt{b})}{a - b}$

Multiply $\sqrt{a b} \sqrt{a}$ .

Tap for more steps...

Combine using the product rule for radicals.

$\frac{\sqrt{a b a} + \sqrt{a b} (- \sqrt{b})}{a - b}$

Raise $a$ to the power of $1$ .

$\frac{\sqrt{a^{1} a b} + \sqrt{a b} (- \sqrt{b})}{a - b}$

Raise $a$ to the power of $1$ .

$\frac{\sqrt{a^{1} a^{1} b} + \sqrt{a b} (- \sqrt{b})}{a - b}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sqrt{a^{1 + 1} b} + \sqrt{a b} (- \sqrt{b})}{a - b}$

Add $1$ and $1$ .

$\frac{\sqrt{a^{2} b} + \sqrt{a b} (- \sqrt{b})}{a - b}$

Simplify terms.

Tap for more steps...

Rewrite using the commutative property of multiplication.

$\frac{\sqrt{a^{2} b} - \sqrt{a b} \sqrt{b}}{a - b}$

Simplify each term.

Tap for more steps...

Pull terms out from under the radical.

$\frac{a \sqrt{b} - \sqrt{a b} \sqrt{b}}{a - b}$

Multiply $- \sqrt{a b} \sqrt{b}$ .

Tap for more steps...

Combine using the product rule for radicals.

$\frac{a \sqrt{b} - \sqrt{b (a b)}}{a - b}$

Raise $b$ to the power of $1$ .

$\frac{a \sqrt{b} - \sqrt{a (b^{1} b)}}{a - b}$

Raise $b$ to the power of $1$ .

$\frac{a \sqrt{b} - \sqrt{a (b^{1} b^{1})}}{a - b}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{a \sqrt{b} - \sqrt{a b^{1 + 1}}}{a - b}$

Add $1$ and $1$ .

$\frac{a \sqrt{b} - \sqrt{a b^{2}}}{a - b}$

Reorder $a$ and $b^{2}$ .

$\frac{a \sqrt{b} - \sqrt{b^{2} a}}{a - b}$

Pull terms out from under the radical.

$\frac{a \sqrt{b} - b \sqrt{a}}{a - b}$

Simplify the numerator.

Tap for more steps...

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{b}$ as $b^{\frac{1}{2}}$ .

$\frac{a b^{\frac{1}{2}} - b \sqrt{a}}{a - b}$

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{a}$ as $a^{\frac{1}{2}}$ .

$\frac{a b^{\frac{1}{2}} - b a^{\frac{1}{2}}}{a - b}$

Factor $a^{\frac{1}{2}} b^{\frac{1}{2}}$ out of $a b^{\frac{1}{2}} - b a^{\frac{1}{2}}$ .

Tap for more steps...

Move $b$ .

$\frac{a b^{\frac{1}{2}} - 1 a^{\frac{1}{2}} b}{a - b}$

Factor $a^{\frac{1}{2}} b^{\frac{1}{2}}$ out of $a b^{\frac{1}{2}}$ .

$\frac{a^{\frac{1}{2}} b^{\frac{1}{2}} (a^{\frac{1}{2}}) - 1 a^{\frac{1}{2}} b}{a - b}$

Factor $a^{\frac{1}{2}} b^{\frac{1}{2}}$ out of $- 1 a^{\frac{1}{2}} b$ .

$\frac{a^{\frac{1}{2}} b^{\frac{1}{2}} (a^{\frac{1}{2}}) + a^{\frac{1}{2}} b^{\frac{1}{2}} (- b^{\frac{1}{2}})}{a - b}$

Factor $a^{\frac{1}{2}} b^{\frac{1}{2}}$ out of $a^{\frac{1}{2}} b^{\frac{1}{2}} (a^{\frac{1}{2}}) + a^{\frac{1}{2}} b^{\frac{1}{2}} (- b^{\frac{1}{2}})$ .

$\frac{a^{\frac{1}{2}} b^{\frac{1}{2}} (a^{\frac{1}{2}} - b^{\frac{1}{2}})}{a - b}$

Do you know how to Evaluate ( square root of ab)/( square root of a+ square root of b)? If not, you can write to our math experts in our application. The best solution for your task you can find above on this page.