Factor x^3-64

$x^{3} - 64$

Rewrite $64$ as $4^{3}$ .

$x^{3} - 4^{3}$

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = x$ and $b = 4$ .

$(x - 4) (x^{2} + x \cdot 4 + 4^{2})$

Simplify.

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Move $4$ to the left of $x$ .

$(x - 4) (x^{2} + 4 x + 4^{2})$

Raise $4$ to the power of $2$ .

$(x - 4) (x^{2} + 4 x + 16)$

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