Factor x^2-8x+16

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Algebra

Factor x^2-8x+16

$x^{2} - 8 x + 16$

Rewrite $16$ as $4^{2}$ .

$x^{2} - 8 x + 4^{2}$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$8 x = 2 \cdot x \cdot 4$

Rewrite the polynomial.

$x^{2} - 2 \cdot x \cdot 4 + 4^{2}$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = x$ and $b = 4$ .

${(x - 4)}^{2}$

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