Factor 27x^3-1

$27 x^{3} - 1$

Rewrite $27 x^{3}$ as ${(3 x)}^{3}$ .

${(3 x)}^{3} - 1$

Rewrite $1$ as $1^{3}$ .

${(3 x)}^{3} - 1^{3}$

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 3 x$ and $b = 1$ .

$(3 x - 1) ({(3 x)}^{2} + 3 x \cdot 1 + 1^{2})$

Simplify.

Tap for more steps...

Apply the product rule to $3 x$ .

$(3 x - 1) (3^{2} x^{2} + 3 x \cdot 1 + 1^{2})$

Raise $3$ to the power of $2$ .

$(3 x - 1) (9 x^{2} + 3 x \cdot 1 + 1^{2})$

Multiply $3$ by $1$ .

$(3 x - 1) (9 x^{2} + 3 x + 1^{2})$

One to any power is one.

$(3 x - 1) (9 x^{2} + 3 x + 1)$

Do you know how to Factor 27x^3-1? If not, you can write to our math experts in our application. The best solution for your task you can find above on this page.

Evaluate 7/4

Evaluate 5/12

Graph f(x)=x^2-8x+15

Solve Using the Quadratic Formula 3x^2-2x-5=0

Evaluate (-625)^(1/4)