Evaluate cube root of 40

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Algebra

$\sqrt[3]{40}$

Rewrite $40$ as $2^{3} \cdot 5$ .

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Factor $8$ out of $40$ .

$\sqrt[3]{8 (5)}$

Rewrite $8$ as $2^{3}$ .

$\sqrt[3]{2^{3} \cdot 5}$

Pull terms out from under the radical.

$2 \sqrt[3]{5}$

The result can be shown in multiple forms.

Exact Form:

$2 \sqrt[3]{5}$

Decimal Form:

$3.41995189 \dots$

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