Simplify square root of x^7

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Algebra

$\sqrt{x^{7}}$

Rewrite $x^{7}$ as ${(x^{3})}^{2} x$ .

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Factor out $x^{6}$ .

$\sqrt{x^{6} x}$

Rewrite $x^{6}$ as ${(x^{3})}^{2}$ .

$\sqrt{{(x^{3})}^{2} x}$

Pull terms out from under the radical.

$x^{3} \sqrt{x}$

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