Solve for x square root of 2x+12=x-6

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Algebra

$\sqrt{2 x + 12} = x - 6$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{2 x + 12}}^{2} = {(x - 6)}^{2}$

Simplify each side of the equation.

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Multiply the exponents in ${({(2 x + 12)}^{\frac{1}{2}})}^{2}$ .

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Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(2 x + 12)}^{\frac{1}{2} \cdot 2} = {(x - 6)}^{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

${(2 x + 12)}^{\frac{1}{2} \cdot 2} = {(x - 6)}^{2}$

Rewrite the expression.

${(2 x + 12)}^{1} = {(x - 6)}^{2}$

Simplify.

$2 x + 12 = {(x - 6)}^{2}$

Solve for $x$ .

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Simplify ${(x - 6)}^{2}$ .

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Rewrite ${(x - 6)}^{2}$ as $(x - 6) (x - 6)$ .

$2 x + 12 = (x - 6) (x - 6)$

Expand $(x - 6) (x - 6)$ using the FOIL Method.

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Apply the distributive property.

$2 x + 12 = x (x - 6) - 6 (x - 6)$

Apply the distributive property.

$2 x + 12 = x \cdot x + x \cdot - 6 - 6 (x - 6)$

Apply the distributive property.

$2 x + 12 = x \cdot x + x \cdot - 6 - 6 x - 6 \cdot - 6$

Simplify and combine like terms.

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Simplify each term.

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Multiply $x$ by $x$ .

$2 x + 12 = x^{2} + x \cdot - 6 - 6 x - 6 \cdot - 6$

Move $- 6$ to the left of $x$ .

$2 x + 12 = x^{2} - 6 \cdot x - 6 x - 6 \cdot - 6$

Multiply $- 6$ by $- 6$ .

$2 x + 12 = x^{2} - 6 x - 6 x + 36$

Subtract $6 x$ from $- 6 x$ .

$2 x + 12 = x^{2} - 12 x + 36$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x^{2} - 12 x + 36 = 2 x + 12$

Move all terms containing $x$ to the left side of the equation.

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Subtract $2 x$ from both sides of the equation.

$x^{2} - 12 x + 36 - 2 x = 12$

Subtract $2 x$ from $- 12 x$ .

$x^{2} - 14 x + 36 = 12$

Move $12$ to the left side of the equation by subtracting it from both sides.

$x^{2} - 14 x + 36 - 12 = 0$

Subtract $12$ from $36$ .

$x^{2} - 14 x + 24 = 0$

Factor $x^{2} - 14 x + 24$ using the AC method.

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Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $24$ and whose sum is $- 14$ .

$- 12, - 2$

Write the factored form using these integers.

$(x - 12) (x - 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 12 = 0$

$x - 2 = 0$

Set the first factor equal to $0$ and solve.

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Set the first factor equal to $0$ .

$x - 12 = 0$

Add $12$ to both sides of the equation.

$x = 12$

Set the next factor equal to $0$ and solve.

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Set the next factor equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

The final solution is all the values that make $(x - 12) (x - 2) = 0$ true.

$x = 12, 2$

Exclude the solutions that do not make $\sqrt{2 x + 12} = x - 6$ true.

$x = 12$

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