Solve for d A=1/2h(c+d)

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Algebra

$A = \frac{1}{2} h (c + d)$

Rewrite the equation as $\frac{1}{2} \cdot (h (c + d)) = A$ .

$\frac{1}{2} \cdot (h (c + d)) = A$

Multiply both sides of the equation by $2$ .

$2 \cdot \frac{1}{2} \cdot (h (c + d)) = 2 \cdot A$

Simplify $2 \cdot \frac{1}{2} \cdot (h (c + d))$ .

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Cancel the common factor of $2$ .

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Cancel the common factor.

$2 \cdot \frac{1}{2} \cdot (h (c + d)) = 2 \cdot A$

Rewrite the expression.

$1 \cdot (h (c + d)) = 2 \cdot A$

Multiply $h (c + d)$ by $1$ .

$h (c + d) = 2 \cdot A$

Apply the distributive property.

$h c + h d = 2 \cdot A$

$h c + h d = 2 A$

Subtract $h c$ from both sides of the equation.

$h d = 2 A - h c$

Divide each term by $h$ and simplify.

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Divide each term in $h d = 2 A - h c$ by $h$ .

$\frac{h d}{h} = \frac{2 A}{h} + \frac{- h c}{h}$

Cancel the common factor of $h$ .

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Cancel the common factor.

$\frac{h d}{h} = \frac{2 A}{h} + \frac{- h c}{h}$

Divide $d$ by $1$ .

$d = \frac{2 A}{h} + \frac{- h c}{h}$

Simplify each term.

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Cancel the common factor of $h$ .

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Cancel the common factor.

$d = \frac{2 A}{h} + \frac{- h c}{h}$

Divide $- 1 c$ by $1$ .

$d = \frac{2 A}{h} - 1 c$

Rewrite $- 1 c$ as $- c$ .

$d = \frac{2 A}{h} - c$

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