Find the Roots (Zeros) y=(x+2)(x-4)(x-6)

$y = (x + 2) (x - 4) (x - 6)$

Set $(x + 2) (x - 4) (x - 6)$ equal to $0$ .

$(x + 2) (x - 4) (x - 6) = 0$

Solve for $x$ .

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If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 2 = 0$

$x - 4 = 0$

$x - 6 = 0$

Set the first factor equal to $0$ and solve.

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Set the first factor equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

Set the next factor equal to $0$ and solve.

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Set the next factor equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

Set the next factor equal to $0$ and solve.

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Set the next factor equal to $0$ .

$x - 6 = 0$

Add $6$ to both sides of the equation.

$x = 6$

The final solution is all the values that make $(x + 2) (x - 4) (x - 6) = 0$ true.

$x = - 2, 4, 6$

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