Solve for x in Radians sin(1/4x)=0

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Trigonometry

$\sin (\frac{1}{4} x) = 0$

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$\frac{1}{4} x = \arcsin (0)$

Simplify the left side.

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Combine $\frac{1}{4}$ and $x$ .

$\frac{x}{4} = \arcsin (0)$

Simplify the right side.

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The exact value of $\arcsin (0)$ is $0$ .

$\frac{x}{4} = 0$

Set the numerator equal to zero.

$x = 0$

The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $π$ to find the solution in the second quadrant.

$\frac{x}{4} = π - 0$

Solve for $x$ .

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Multiply both sides of the equation by $4$ .

$4 \frac{x}{4} = 4 (π - 0)$

Simplify both sides of the equation.

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Simplify the left side.

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Cancel the common factor of $4$ .

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Cancel the common factor.

$4 \frac{x}{4} = 4 (π - 0)$

Rewrite the expression.

$x = 4 (π - 0)$

Simplify the right side.

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Subtract $0$ from $π$ .

$x = 4 π$

Find the period of $\sin (\frac{1}{4} x)$ .

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The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $\frac{1}{4}$ in the formula for period.

$\frac{2 π}{| \frac{1}{4} |}$

$\frac{1}{4}$ is approximately $0.25$ which is positive so remove the absolute value

$\frac{2 π}{\frac{1}{4}}$

Multiply the numerator by the reciprocal of the denominator.

$2 π \cdot 4$

Multiply $4$ by $2$ .

$8 π$

The period of the $\sin (\frac{1}{4} x)$ function is $8 π$ so values will repeat every $8 π$ radians in both directions.

$x = 8 π n, 4 π + 8 π n$ , for any integer $n$

Consolidate the answers.

$x = 4 π n$ , for any integer $n$

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