Solve for x in Degrees 2sin(x)- square root of 3=0

Solve Math

Trigonometry

$2 \sin (x) - \sqrt{3} = 0$

Add $\sqrt{3}$ to both sides of the equation.

$2 \sin (x) = \sqrt{3}$

Divide each term in $2 \sin (x) = \sqrt{3}$ by $2$ and simplify.

Tap for more steps...

Divide each term in $2 \sin (x) = \sqrt{3}$ by $2$ .

$\frac{2 \sin (x)}{2} = \frac{\sqrt{3}}{2}$

Simplify the left side.

Tap for more steps...

Cancel the common factor of $2$ .

Tap for more steps...

Cancel the common factor.

$\frac{2 \sin (x)}{2} = \frac{\sqrt{3}}{2}$

Divide $\sin (x)$ by $1$ .

$\sin (x) = \frac{\sqrt{3}}{2}$

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$x = \arcsin (\frac{\sqrt{3}}{2})$

Simplify the right side.

Tap for more steps...

The exact value of $\arcsin (\frac{\sqrt{3}}{2})$ is $60$ .

$x = 60$

The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $180$ to find the solution in the second quadrant.

$x = 180 - 60$

Subtract $60$ from $180$ .

$x = 120$

Find the period of $\sin (x)$ .

Tap for more steps...

The period of the function can be calculated using $\frac{360}{| b |}$ .

$\frac{360}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{360}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{360}{1}$

Divide $360$ by $1$ .

$360$

The period of the $\sin (x)$ function is $360$ so values will repeat every $360$ degrees in both directions.

$x = 60 + 360 n, 120 + 360 n$ , for any integer $n$

Do you know how to Solve for x in Degrees 2sin(x)- square root of 3=0? If not, you can write to our math experts in our application. The best solution for your task you can find above on this page.