Solve for x in Radians sin(3x)=-( square root of 3)/2

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Trigonometry

$\sin (3 x) = - \frac{\sqrt{3}}{2}$

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$3 x = \arcsin (- \frac{\sqrt{3}}{2})$

Simplify the right side.

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The exact value of $\arcsin (- \frac{\sqrt{3}}{2})$ is $- \frac{π}{3}$ .

$3 x = - \frac{π}{3}$

Divide each term in $3 x = - \frac{π}{3}$ by $3$ and simplify.

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Divide each term in $3 x = - \frac{π}{3}$ by $3$ .

$\frac{3 x}{3} = \frac{- \frac{π}{3}}{3}$

Simplify the left side.

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Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 x}{3} = \frac{- \frac{π}{3}}{3}$

Divide $x$ by $1$ .

$x = \frac{- \frac{π}{3}}{3}$

Simplify the right side.

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Multiply the numerator by the reciprocal of the denominator.

$x = - \frac{π}{3} \cdot \frac{1}{3}$

Multiply $- \frac{π}{3} \cdot \frac{1}{3}$ .

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Multiply $\frac{1}{3}$ by $\frac{π}{3}$ .

$x = - \frac{π}{3 \cdot 3}$

Multiply $3$ by $3$ .

$x = - \frac{π}{9}$

The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from $2 π$ , to find a reference angle. Next, add this reference angle to $π$ to find the solution in the third quadrant.

$3 x = 2 π + \frac{π}{3} + π$

Simplify the expression to find the second solution.

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Subtract $2 π$ from $2 π + \frac{π}{3} + π$ .

$3 x = 2 π + \frac{π}{3} + π - 2 π$

The resulting angle of $\frac{4 π}{3}$ is positive, less than $2 π$ , and coterminal with $2 π + \frac{π}{3} + π$ .

$3 x = \frac{4 π}{3}$

Divide each term in $3 x = \frac{4 π}{3}$ by $3$ and simplify.

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Divide each term in $3 x = \frac{4 π}{3}$ by $3$ .

$\frac{3 x}{3} = \frac{\frac{4 π}{3}}{3}$

Simplify the left side.

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Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 x}{3} = \frac{\frac{4 π}{3}}{3}$

Divide $x$ by $1$ .

$x = \frac{\frac{4 π}{3}}{3}$

Simplify the right side.

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Multiply the numerator by the reciprocal of the denominator.

$x = \frac{4 π}{3} \cdot \frac{1}{3}$

Multiply $\frac{4 π}{3} \cdot \frac{1}{3}$ .

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Multiply $\frac{4 π}{3}$ by $\frac{1}{3}$ .

$x = \frac{4 π}{3 \cdot 3}$

Multiply $3$ by $3$ .

$x = \frac{4 π}{9}$

Find the period of $\sin (3 x)$ .

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The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $3$ in the formula for period.

$\frac{2 π}{| 3 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $3$ is $3$ .

$\frac{2 π}{3}$

Add $\frac{2 π}{3}$ to every negative angle to get positive angles.

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Add $\frac{2 π}{3}$ to $- \frac{π}{9}$ to find the positive angle.

$- \frac{π}{9} + \frac{2 π}{3}$

To write $\frac{2 π}{3}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{2 π}{3} \cdot \frac{3}{3} - \frac{π}{9}$

Write each expression with a common denominator of $9$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{2 π}{3}$ by $\frac{3}{3}$ .

$\frac{2 π \cdot 3}{3 \cdot 3} - \frac{π}{9}$

Multiply $3$ by $3$ .

$\frac{2 π \cdot 3}{9} - \frac{π}{9}$

Combine the numerators over the common denominator.

$\frac{2 π \cdot 3 - π}{9}$

Simplify the numerator.

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Multiply $3$ by $2$ .

$\frac{6 π - π}{9}$

Subtract $π$ from $6 π$ .

$\frac{5 π}{9}$

List the new angles.

$x = \frac{5 π}{9}$

The period of the $\sin (3 x)$ function is $\frac{2 π}{3}$ so values will repeat every $\frac{2 π}{3}$ radians in both directions.

$x = \frac{4 π}{9} + \frac{2 π n}{3}, \frac{5 π}{9} + \frac{2 π n}{3}$ , for any integer $n$

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