Find the Exact Value tan(-pi/6)

$\tan (- \frac{π}{6})$

Add full rotations of $2 π$ until the angle is between $0$ and $2 π$ .

$\tan (\frac{11 π}{6})$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because tangent is negative in the fourth quadrant.

$- \tan (\frac{π}{6})$

The exact value of $\tan (\frac{π}{6})$ is $\frac{\sqrt{3}}{3}$ .

$- \frac{\sqrt{3}}{3}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{\sqrt{3}}{3}$

Decimal Form:

$- 0.57735026 \dots$

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