Take the inverse cotangent of both sides of the equation to extract <math><mstyle displaystyle="true"><mi>x</mi></mstyle></math> from inside the cotangent.

Evaluate <math><mstyle displaystyle="true"><mi>arccot</mi><mrow><mo>(</mo><mfrac><mrow><mn>3</mn></mrow><mrow><mn>4</mn></mrow></mfrac><mo>)</mo></mrow></mstyle></math> .

The cotangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> to find the solution in the fourth quadrant.

Remove the parentheses around the expression <math><mstyle displaystyle="true"><mn>3.14159265</mn></mstyle></math> .

Add <math><mstyle displaystyle="true"><mn>3.14159265</mn></mstyle></math> and <math><mstyle displaystyle="true"><mn>0.92729521</mn></mstyle></math> .

The period of the function can be calculated using <math><mstyle displaystyle="true"><mfrac><mrow><mi>π</mi></mrow><mrow><mrow><mo>|</mo><mi>b</mi><mo>|</mo></mrow></mrow></mfrac></mstyle></math> .

Replace <math><mstyle displaystyle="true"><mi>b</mi></mstyle></math> with <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> in the formula for period.

Solve the equation.

The absolute value is the distance between a number and zero. The distance between <math><mstyle displaystyle="true"><mn>0</mn></mstyle></math> and <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> is <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> .

Divide <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> by <math><mstyle displaystyle="true"><mn>1</mn></mstyle></math> .

The period of the <math><mstyle displaystyle="true"><mi>cot</mi><mrow><mo>(</mo><mi>x</mi><mo>)</mo></mrow></mstyle></math> function is <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> so values will repeat every <math><mstyle displaystyle="true"><mi>π</mi></mstyle></math> radians in both directions.

Consolidate the answers.

Do you know how to Solve for ? cot(x)=3/4? If not, you can write to our math experts in our application. The best solution for your task you can find above on this page.

Name | one billion nine hundred twenty-four million three hundred forty-one thousand two hundred sixty |
---|

- 1924341260 has 32 divisors, whose sum is
**5199029712** - The reverse of 1924341260 is
**0621434291** - Previous prime number is
**1613**

- Is Prime? no
- Number parity even
- Number length 10
- Sum of Digits 32
- Digital Root 5

Name | one billion two hundred sixty-six million eight hundred ninety-two thousand nine hundred seven |
---|

- 1266892907 has 8 divisors, whose sum is
**1483192032** - The reverse of 1266892907 is
**7092986621** - Previous prime number is
**41**

- Is Prime? no
- Number parity odd
- Number length 10
- Sum of Digits 50
- Digital Root 5

Name | five hundred sixty-one million one hundred thirty-six thousand one hundred sixty-three |
---|

- 561136163 has 4 divisors, whose sum is
**641298480** - The reverse of 561136163 is
**361631165** - Previous prime number is
**7**

- Is Prime? no
- Number parity odd
- Number length 9
- Sum of Digits 32
- Digital Root 5