Solve Using the Square Root Property x^2+53=0

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Trigonometry

$x^{2} + 53 = 0$

Subtract $53$ from both sides of the equation.

$x^{2} = - 53$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{- 53}$

The complete solution is the result of both the positive and negative portions of the solution.

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Simplify the right side of the equation.

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Rewrite $- 53$ as $- 1 (53)$ .

$x = \pm \sqrt{- 1 \cdot 53}$

Rewrite $\sqrt{- 1 (53)}$ as $\sqrt{- 1} \cdot \sqrt{53}$ .

$x = \pm \sqrt{- 1} \cdot \sqrt{53}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \pm i \sqrt{53}$

The complete solution is the result of both the positive and negative portions of the solution.

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First, use the positive value of the $\pm$ to find the first solution.

$x = i \sqrt{53}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - i \sqrt{53}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = i \sqrt{53}, - i \sqrt{53}$

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Name

Name	six hundred sixty-two million sixty-five thousand eight hundred seventy-six

Interesting facts

662065876 has 16 divisors, whose sum is 1521343296
The reverse of 662065876 is 678560266
Previous prime number is 47

Basic properties

Is Prime? no
Number parity even
Number length 9
Sum of Digits 46
Digital Root 1

Name

Name	one billion two hundred eighty-two million seven hundred seventy-five thousand nine hundred sixty-nine

Interesting facts

1282775969 has 4 divisors, whose sum is 1283450544
The reverse of 1282775969 is 9695772821
Previous prime number is 1907

Basic properties

Is Prime? no
Number parity odd
Number length 10
Sum of Digits 56
Digital Root 2

Name

Name	one billion ninety-five million eight hundred fifty-six thousand nine hundred eighty-two

Interesting facts

1095856982 has 16 divisors, whose sum is 1831375872
The reverse of 1095856982 is 2896585901
Previous prime number is 47

Basic properties

Is Prime? no
Number parity even
Number length 10
Sum of Digits 53
Digital Root 8

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