Graph f(x)=x^2-3x-2

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Trigonometry

Graph f(x)=x^2-3x-2

$f (x) = x^{2} - 3 x - 2$

Find the properties of the given parabola.

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Rewrite the equation in vertex form.

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Complete the square for $x^{2} - 3 x - 2$ .

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Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1, b = - 3, c = - 2$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = - \frac{3}{2 (1)}$

Multiply $2$ by $1$ .

$d = - \frac{3}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Simplify each term.

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Raise $- 3$ to the power of $2$ .

$e = - 2 - \frac{9}{4 (1)}$

Multiply $4$ by $1$ .

$e = - 2 - \frac{9}{4}$

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$e = - 2 \cdot \frac{4}{4} - \frac{9}{4}$

Combine $- 2$ and $\frac{4}{4}$ .

$e = \frac{- 2 \cdot 4}{4} - \frac{9}{4}$

Combine the numerators over the common denominator.

$e = \frac{- 2 \cdot 4 - 9}{4}$

Simplify the numerator.

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Multiply $- 2$ by $4$ .

$e = \frac{- 8 - 9}{4}$

Subtract $9$ from $- 8$ .

$e = \frac{- 17}{4}$

Move the negative in front of the fraction.

$e = - \frac{17}{4}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $a {(x + d)}^{2} + e$ .

${(x - \frac{3}{2})}^{2} - \frac{17}{4}$

Set $y$ equal to the new right side.

$y = {(x - \frac{3}{2})}^{2} - \frac{17}{4}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = \frac{3}{2}$

$k = - \frac{17}{4}$

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Find the vertex $(h, k)$ .

$(\frac{3}{2}, - \frac{17}{4})$

Find $p$ , the distance from the vertex to the focus.

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Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Cancel the common factor of $1$ .

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Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Rewrite the expression.

$\frac{1}{4}$

Find the focus.

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The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(\frac{3}{2}, - 4)$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = \frac{3}{2}$

Find the directrix.

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The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = - \frac{9}{2}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(\frac{3}{2}, - \frac{17}{4})$

Focus: $(\frac{3}{2}, - 4)$

Axis of Symmetry: $x = \frac{3}{2}$

Directrix: $y = - \frac{9}{2}$

Direction: Opens Up

Vertex: $(\frac{3}{2}, - \frac{17}{4})$

Focus: $(\frac{3}{2}, - 4)$

Axis of Symmetry: $x = \frac{3}{2}$

Directrix: $y = - \frac{9}{2}$

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

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Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{2} - 3 \cdot 1 - 2$

Simplify the result.

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Simplify each term.

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One to any power is one.

$f (1) = 1 - 3 \cdot 1 - 2$

Multiply $- 3$ by $1$ .

$f (1) = 1 - 3 - 2$

Simplify by subtracting numbers.

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Subtract $3$ from $1$ .

$f (1) = - 2 - 2$

Subtract $2$ from $- 2$ .

$f (1) = - 4$

The final answer is $- 4$ .

$- 4$

The $y$ value at $x = 1$ is $- 4$ .

$y = - 4$

Replace the variable $x$ with $0$ in the expression.

$f (0) = {(0)}^{2} - 3 \cdot 0 - 2$

Simplify the result.

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Simplify each term.

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Raising $0$ to any positive power yields $0$ .

$f (0) = 0 - 3 \cdot 0 - 2$

Multiply $- 3$ by $0$ .

$f (0) = 0 + 0 - 2$

Simplify by adding and subtracting.

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Add $0$ and $0$ .

$f (0) = 0 - 2$

Subtract $2$ from $0$ .

$f (0) = - 2$

The final answer is $- 2$ .

$- 2$

The $y$ value at $x = 0$ is $- 2$ .

$y = - 2$

Replace the variable $x$ with $3$ in the expression.

$f (3) = {(3)}^{2} - 3 \cdot 3 - 2$

Simplify the result.

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Simplify each term.

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Raise $3$ to the power of $2$ .

$f (3) = 9 - 3 \cdot 3 - 2$

Multiply $- 3$ by $3$ .

$f (3) = 9 - 9 - 2$

Simplify by subtracting numbers.

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Subtract $9$ from $9$ .

$f (3) = 0 - 2$

Subtract $2$ from $0$ .

$f (3) = - 2$

The final answer is $- 2$ .

$- 2$

The $y$ value at $x = 3$ is $- 2$ .

$y = - 2$

Replace the variable $x$ with $4$ in the expression.

$f (4) = {(4)}^{2} - 3 \cdot 4 - 2$

Simplify the result.

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Simplify each term.

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Raise $4$ to the power of $2$ .

$f (4) = 16 - 3 \cdot 4 - 2$

Multiply $- 3$ by $4$ .

$f (4) = 16 - 12 - 2$

Simplify by subtracting numbers.

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Subtract $12$ from $16$ .

$f (4) = 4 - 2$

Subtract $2$ from $4$ .

$f (4) = 2$

The final answer is $2$ .

$2$

The $y$ value at $x = 4$ is $2$ .

$y = 2$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ 0 & - 2 \\ 1 & - 4 \\ \frac{3}{2} & - \frac{17}{4} \\ 3 & - 2 \\ 4 & 2 \end{array}$

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(\frac{3}{2}, - \frac{17}{4})$

Focus: $(\frac{3}{2}, - 4)$

Axis of Symmetry: $x = \frac{3}{2}$

Directrix: $y = - \frac{9}{2}$

$\begin{array}{c} x & y \\ 0 & - 2 \\ 1 & - 4 \\ \frac{3}{2} & - \frac{17}{4} \\ 3 & - 2 \\ 4 & 2 \end{array}$

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