Solve for y |y-3|=7

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Trigonometry

Solve for y |y-3|=7

$| y - 3 | = 7$

Remove the absolute value term. This creates a $\pm$ on the right side of the equation because $| x | = \pm x$ .

$y - 3 = \pm 7$

Set up the positive portion of the $\pm$ solution.

$y - 3 = 7$

Move all terms not containing $y$ to the right side of the equation.

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Add $3$ to both sides of the equation.

$y = 7 + 3$

Add $7$ and $3$ .

$y = 10$

Set up the negative portion of the $\pm$ solution.

$y - 3 = - 7$

Move all terms not containing $y$ to the right side of the equation.

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Add $3$ to both sides of the equation.

$y = - 7 + 3$

Add $- 7$ and $3$ .

$y = - 4$

The solution to the equation includes both the positive and negative portions of the solution.

$y = 10, - 4$

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