Solve for x a(n)=(-1)^(n+1)e^(n^2)

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Trigonometry

$a (n) = {(- 1)}^{n + 1} e^{n^{2}}$

Divide each term in $a (n) = {(- 1)}^{n + 1} e^{n^{2}}$ by $n$ .

$\frac{a (n)}{n} = \frac{{(- 1)}^{n + 1} e^{n^{2}}}{n}$

Cancel the common factor of $n$ .

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Cancel the common factor.

$\frac{a n}{n} = \frac{{(- 1)}^{n + 1} e^{n^{2}}}{n}$

Divide $a$ by $1$ .

$a = \frac{{(- 1)}^{n + 1} e^{n^{2}}}{n}$

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