Solve for x 2sin(2(x))-5sin(x+2)=0

$2 \sin (2 (x)) - 5 \sin (x + 2) = 0$

Multiply $2$ by $x$ .

$2 \sin (2 x) - 5 \sin (x + 2) = 0$

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx 0.73251347 + 2 π n, 4.47039916 + 2 π n$ , for any integer $n$

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