Find Where Undefined/Discontinuous (x^2-4x+4)/(4x-8)

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Trigonometry

$\frac{x^{2} - 4 x + 4}{4 x - 8}$

Set the denominator in $\frac{x^{2} - 4 x + 4}{4 x - 8}$ equal to $0$ to find where the expression is undefined.

$4 x - 8 = 0$

Solve for $x$ .

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Add $8$ to both sides of the equation.

$4 x = 8$

Divide each term by $4$ and simplify.

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Divide each term in $4 x = 8$ by $4$ .

$\frac{4 x}{4} = \frac{8}{4}$

Cancel the common factor of $4$ .

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Cancel the common factor.

$\frac{4 x}{4} = \frac{8}{4}$

Divide $x$ by $1$ .

$x = \frac{8}{4}$

Divide $8$ by $4$ .

$x = 2$

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = 2$

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