Graph 3sin(8x)-6

$3 \sin (8 x) - 6$

Use the form $a \sin (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = 3$

$b = 8$

$c = 0$

$d = - 6$

Find the amplitude $| a |$ .

Amplitude: $3$

Find the period of $3 \sin (8 x)$ .

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The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $8$ in the formula for period.

$\frac{2 π}{| 8 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $8$ is $8$ .

$\frac{2 π}{8}$

Cancel the common factor of $2$ and $8$ .

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Factor $2$ out of $2 π$ .

$\frac{2 (π)}{8}$

Cancel the common factors.

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Factor $2$ out of $8$ .

$\frac{2 π}{2 \cdot 4}$

Cancel the common factor.

$\frac{2 π}{2 \cdot 4}$

Rewrite the expression.

$\frac{π}{4}$

Find the phase shift using the formula $\frac{c}{b}$ .

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The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{0}{8}$

Divide $0$ by $8$ .

Phase Shift: $0$

Find the vertical shift $d$ .

Vertical Shift: $- 6$

List the properties of the trigonometric function.

Amplitude: $3$

Period: $\frac{π}{4}$

Phase Shift: $0$ ( $0$ to the right)

Vertical Shift: $- 6$

Select a few points to graph.

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Find the point at $x = 0$ .

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Replace the variable $x$ with $0$ in the expression.

$f (0) = 3 \sin (8 (0)) - 6$

Simplify the result.

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Simplify each term.

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Multiply $8$ by $0$ .

$f (0) = 3 \sin (0) - 6$

The exact value of $\sin (0)$ is $0$ .

$f (0) = 3 \cdot 0 - 6$

Multiply $3$ by $0$ .

$f (0) = 0 - 6$

Subtract $6$ from $0$ .

$f (0) = - 6$

The final answer is $- 6$ .

$- 6$

Find the point at $x = \frac{π}{16}$ .

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Replace the variable $x$ with $\frac{π}{16}$ in the expression.

$f (\frac{π}{16}) = 3 \sin (8 (\frac{π}{16})) - 6$

Simplify the result.

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Simplify each term.

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Cancel the common factor of $8$ .

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Factor $8$ out of $16$ .

$f (\frac{π}{16}) = 3 \sin (8 (\frac{π}{8 (2)})) - 6$

Cancel the common factor.

$f (\frac{π}{16}) = 3 \sin (8 (\frac{π}{8 \cdot 2})) - 6$

Rewrite the expression.

$f (\frac{π}{16}) = 3 \sin (\frac{π}{2}) - 6$

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (\frac{π}{16}) = 3 \cdot 1 - 6$

Multiply $3$ by $1$ .

$f (\frac{π}{16}) = 3 - 6$

Subtract $6$ from $3$ .

$f (\frac{π}{16}) = - 3$

The final answer is $- 3$ .

$- 3$

Find the point at $x = \frac{π}{8}$ .

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Replace the variable $x$ with $\frac{π}{8}$ in the expression.

$f (\frac{π}{8}) = 3 \sin (8 (\frac{π}{8})) - 6$

Simplify the result.

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Simplify each term.

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Cancel the common factor of $8$ .

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Cancel the common factor.

$f (\frac{π}{8}) = 3 \sin (8 (\frac{π}{8})) - 6$

Rewrite the expression.

$f (\frac{π}{8}) = 3 \sin (π) - 6$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$f (\frac{π}{8}) = 3 \sin (0) - 6$

The exact value of $\sin (0)$ is $0$ .

$f (\frac{π}{8}) = 3 \cdot 0 - 6$

Multiply $3$ by $0$ .

$f (\frac{π}{8}) = 0 - 6$

Subtract $6$ from $0$ .

$f (\frac{π}{8}) = - 6$

The final answer is $- 6$ .

$- 6$

Find the point at $x = \frac{3 π}{16}$ .

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Replace the variable $x$ with $\frac{3 π}{16}$ in the expression.

$f (\frac{3 π}{16}) = 3 \sin (8 (\frac{3 π}{16})) - 6$

Simplify the result.

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Simplify each term.

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Cancel the common factor of $8$ .

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Factor $8$ out of $16$ .

$f (\frac{3 π}{16}) = 3 \sin (8 (\frac{3 π}{8 (2)})) - 6$

Cancel the common factor.

$f (\frac{3 π}{16}) = 3 \sin (8 (\frac{3 π}{8 \cdot 2})) - 6$

Rewrite the expression.

$f (\frac{3 π}{16}) = 3 \sin (\frac{3 π}{2}) - 6$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the fourth quadrant.

$f (\frac{3 π}{16}) = 3 (- \sin (\frac{π}{2})) - 6$

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$f (\frac{3 π}{16}) = 3 (- 1 \cdot 1) - 6$

Multiply $- 1$ by $1$ .

$f (\frac{3 π}{16}) = 3 \cdot - 1 - 6$

Multiply $3$ by $- 1$ .

$f (\frac{3 π}{16}) = - 3 - 6$

Subtract $6$ from $- 3$ .

$f (\frac{3 π}{16}) = - 9$

The final answer is $- 9$ .

$- 9$

Find the point at $x = \frac{π}{4}$ .

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Replace the variable $x$ with $\frac{π}{4}$ in the expression.

$f (\frac{π}{4}) = 3 \sin (8 (\frac{π}{4})) - 6$

Simplify the result.

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Simplify each term.

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Cancel the common factor of $4$ .

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Factor $4$ out of $8$ .

$f (\frac{π}{4}) = 3 \sin (4 (2) (\frac{π}{4})) - 6$

Cancel the common factor.

$f (\frac{π}{4}) = 3 \sin (4 \cdot (2 (\frac{π}{4}))) - 6$

Rewrite the expression.

$f (\frac{π}{4}) = 3 \sin (2 π) - 6$

Subtract full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$f (\frac{π}{4}) = 3 \sin (0) - 6$

The exact value of $\sin (0)$ is $0$ .

$f (\frac{π}{4}) = 3 \cdot 0 - 6$

Multiply $3$ by $0$ .

$f (\frac{π}{4}) = 0 - 6$

Subtract $6$ from $0$ .

$f (\frac{π}{4}) = - 6$

The final answer is $- 6$ .

$- 6$

List the points in a table.

$\begin{array}{c} x & f (x) \\ 0 & - 6 \\ \frac{π}{16} & - 3 \\ \frac{π}{8} & - 6 \\ \frac{3 π}{16} & - 9 \\ \frac{π}{4} & - 6 \end{array}$

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude: $3$

Period: $\frac{π}{4}$

Phase Shift: $0$ ( $0$ to the right)

Vertical Shift: $- 6$

$\begin{array}{c} x & f (x) \\ 0 & - 6 \\ \frac{π}{16} & - 3 \\ \frac{π}{8} & - 6 \\ \frac{3 π}{16} & - 9 \\ \frac{π}{4} & - 6 \end{array}$

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