Evaluate v((- square root of 3)^2+(1)^2)

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Trigonometry

$v ({(- \sqrt{3})}^{2} + {(1)}^{2})$

Simplify each term.

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Apply the product rule to $- \sqrt{3}$ .

$v ({(- 1)}^{2} {\sqrt{3}}^{2} + {(1)}^{2})$

Raise $- 1$ to the power of $2$ .

$v (1 {\sqrt{3}}^{2} + {(1)}^{2})$

Multiply ${\sqrt{3}}^{2}$ by $1$ .

$v ({\sqrt{3}}^{2} + {(1)}^{2})$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

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Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$v ({(3^{\frac{1}{2}})}^{2} + {(1)}^{2})$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$v (3^{\frac{1}{2} \cdot 2} + {(1)}^{2})$

Combine $\frac{1}{2}$ and $2$ .

$v (3^{\frac{2}{2}} + {(1)}^{2})$

Cancel the common factor of $2$ .

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Cancel the common factor.

$v (3^{\frac{2}{2}} + {(1)}^{2})$

Divide $1$ by $1$ .

$v (3^{1} + {(1)}^{2})$

Evaluate the exponent.

$v (3 + {(1)}^{2})$

One to any power is one.

$v (3 + 1)$

Simplify the expression.

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Add $3$ and $1$ .

$v \cdot 4$

Move $4$ to the left of $v$ .

$4 v$

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Name

Name	one billion four hundred fifty-seven million seven hundred fifty-eight thousand eight hundred eighty-five

Interesting facts

1457758885 has 8 divisors, whose sum is 1908338976
The reverse of 1457758885 is 5888577541
Previous prime number is 11

Basic properties

Is Prime? no
Number parity odd
Number length 10
Sum of Digits 58
Digital Root 4

Name

Name	one billion three hundred forty-three million six hundred fifty-six thousand two hundred sixteen

Interesting facts

1343656216 has 64 divisors, whose sum is 5186656800
The reverse of 1343656216 is 6126563431
Previous prime number is 1409

Basic properties

Is Prime? no
Number parity even
Number length 10
Sum of Digits 37
Digital Root 1

Name

Name	one billion nine hundred nine million seven hundred seventy-two thousand twenty-two

Interesting facts

1909772022 has 8 divisors, whose sum is 3819544056
The reverse of 1909772022 is 2202779091
Previous prime number is 3

Basic properties

Is Prime? no
Number parity even
Number length 10
Sum of Digits 39
Digital Root 3

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