Find Trig Functions Using Identities cos(theta)=5/13

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Trigonometry

$\cos (θ) = \frac{5}{13}$

To find the value of $\sec (θ)$ , use the fact that $\frac{1}{\cos (θ)}$ then substitute in the known values.

$\sec (θ) = \frac{1}{\cos (θ)} = \frac{1}{\frac{5}{13}}$

Simplify the result.

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Multiply the numerator by the reciprocal of the denominator.

$\sec (θ) = \frac{1}{\cos (θ)} = 1 (\frac{13}{5})$

Multiply $\frac{13}{5}$ by $1$ .

$\sec (θ) = \frac{1}{\cos (θ)} = \frac{13}{5}$

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